Two stupid ip questions;

mdavis@kieser.net mdavis@kieser.net
Mon, 31 May 1999 19:25:27 -0400


Hi,

As far as I know, it's 10.x.x.x; 192.x.x.x 224.x.x.x  ; I could be 
wrong about the 224.

Anyway, as for the second question, I haven't really seen it being 
used that way, except in text books! Basically an IP address is 
divided into 4 numbers, seperated by the dots... if you convert 
these numbers to hex individually, concatenate them and then 
convert them back from hex, you'll get your number! Obviously you 
can reverse this to get back to the original ip address.

So, 216.33.20.4 = D8 21 14 04 (in HEX) = 
3626046468
I used the windoze calulator.

Mike Davis
mdavis@kieser.net





Date sent:      	Mon, 31 May 1999 21:47:15 +0100
To:             	beowulf@beowulf.gsfc.nasa.gov
From:           	Simon Hogg <s.hogg@ic.ac.uk>
Subject:        	Two stupid ip questions;

> Just two quick questions for now - I only have accesss to email at the
> moment (well for a couple of days, so ...)
> 
> 1)  what are the reserved ip numbers for the network 'internal' to the
> beowulf?  (I *thought* it was 192.x.x.x but I just want to check?
> 
> 2)  what's with these ip addresses with no dots?  Is this in an rfc or
> something? (or is it straight decimal to hex conversion?)  e.g.
> http://3626046468/ maps to www.angelfire.com (216.33.20.4)
> 
> Thanks.
> 
> 
> 
> --	 Simon Hogg, Research Assistant,
> 	 RCA/V&A Conservation Course,
> 	 Victoria and Albert Museum,
> 	 London, SW7 2RL, UK
> Tel.	 +44 (0)171 938 8685
> Fax.	 +44 (0)171 938 8661
> Mobile: +44 (0)7788 870 550
> Email:	 s.hogg@vam.ac.uk   s.hogg@ic.ac.uk