[Beowulf] UPS & power supply instability
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Robert G. Brown rgb at phy.duke.eduWed Sep 28 16:03:38 PDT 2005
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Jim Lux writes: > But, what you're really concerned about is harmonic content in the load > current, not the phase, per se. If you hooked a big inductive load up, the > current would lag the voltage but still be sinusoidal, and you might not > have any problems. > > Just as an example.. if the third harmonic current were equal to the > fundamental (i.e. equal power in the harmonic and the fundamental), the PF > would be .707. (and, in a three phase system, the neutral current would be > 3*.71 * leg current) If you have a hard time understanding what Jim is talking about with his third harmonic stuff, visit the mirus international link and look at the pictures. It just means that a switching power supply typically draws most of its current in the middle third of each half phase, or (for V(t) = V_0 sin(120\pi t) (\omega = 2 \pi f with f = 60 Hz) the current is drawn only when \omega t \in [\pi/3,2\pi/3] or [4\pi/3,5\pi/3]. The current is thus IN PHASE with the voltage -- it is drawn in 60 Hz pulses in phase with V(t) -- but current is drawn basically only when the voltage crosses a fixed threshold. Now it is a True Fact that I_0 sin(\omega t) + I_0 sin(\omega t + 2\pi/3) + I_0 sin (\omega t + 4\pi/3) = 0 This is the expected cancellation on a shared neutral wire for three balanced perfectly resistive loads. It is also a True Fact that the shared neutral current on three lines that only draw in the middle third of the half cycle DO NOT OVERLAP -- the period is broken up into sixths and in each sixth cycle one and only one line is drawing and dumping current. Furthermore, it is drawing a peak current that is LARGER than you'd expect from the rms power consumption. So instead of cancelling, you have a line current on the neutral that is something like I_0 sin(3\omega t), or the third harmonic of the base frequency \omega. As Jim noted, EACH cycle of this current would carry as much as any single line, so your rms current (think "average" for the purpose of determining e.g. line heating, voltage drop on the neutral, and so on) is 3x as great. Line heating is given by I^2 R, so 3x the current is 9x the joule heating of the neutral line and will ALSO produce overheating in your primary three phase transformer, reducing its lifetime if nothing worse. Carrying 60 amps (give or take) on a line that's safe at 20 amps is a Bad Idea. You can often tell you've got a shared neutral switching power supply by grabbing the shared neutral (by the insulation, of course:-). If you go "ouch" and let go -- well, a normal 12/2 line carrying 20 amps should be no more than just barely warm, so it won't e.g. set your house on fire inside the walls even if it is wrapped in wall insulation that partially traps the heat, on a hot day. On our cluster, the circuit breakers were quite hot indeed until we had it rewired, and we couldn't run any circuit at much more than 50% of theoretical load without popping the line breaker. rgb -------------- next part -------------- A non-text attachment was scrubbed... Name: not available Type: application/pgp-signature Size: 189 bytes Desc: not available Url : http://www.scyld.com/pipermail/beowulf/attachments/20050928/05313039/attachment.bin
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