How can I compute the range of signed and unsigned types

[James Cownie]

Jag wrote : -

> Those sizes are defined for the C language.  In order words, no
> matter if you're on a 32-bit machine or a 64-bit machine, an int is
> always going to be 32-bit and thus have the same numeric range
> because the standards say so.  This goes for all the basic types,
> not just int's.

No, the C standard says nothing of the sort.

All the C standard says is that

1) sizeof (char)  == 1
2) sizeof (short) >= sizeof (char)
3) sizeof (int)   >= sizeof (short)
4) sizeof (long)  >= sizeof (int)
5) sizeof (long long) >= sizeof (long).

It also does not specify that the representation of an int is two's
complement, so even on machines with the same sizeof(int) the legal
ranges could differ.

-- Jim 

James Cownie	<jcownie at etnus.com>
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